Some more array tasks:

Assume ' a' is an array of real numbers and is instantiated. 1)    display all of the values in array a,  one per line. for (int    x    =    0;    x    <    a.length;    x + +) { IO.println (a [x]); } 2)    add 10 to each element of array a. for (int    x    =    0;    x    <    a.length;    x + +) { a [x]    =    a [x]    +    10; } 3)    assign the largest value in array a to the variable ' max'    -    which must be declared.    Assume a has at least one element. int max    =    a [0]; for (int    x    =    1;    x    <    a.length;    x + +) { if (a [x]    >    max) { max    =    a [x]; } }   4)    make a copy of array a.   call the copy c. int c []    =    new int [a.length]; for (int    x    =    0;    x    <    a.length;    x + +) { c [x]    =    a [x]; } 5)    swap the first two values in array a. int temp    =    a [0]; a [0]    =    a [1]; a [1]    =    temp;

 

CG then demonstrated the use of an integer array with the following problem:

Read several (at least one) positive integers and display all of the integers which are greater than their average value.  For example,  the input:    10    4    15    7    - 1 Yields the output:    10    15  Our solution will feature the global procedural architecture.  / /    The main method. static public void main (~ ~ ~ ~) { readAndStoreTheNumbers (); computeTheAverage (); displayTheNumbersAboveAverage ();   / /    Data Dictionary static private int a []; static private final int LIMIT = 1000; static private double average; static private int nrElements; static private int number;  / /    Refine the methods. static private void readAndStoreTheNumbers () { a    =    new int [LIMIT]; nrElements    =    0; number    =    IO.read_int (); while (number    >    0) { a [nrElements]    =    number; nrElements    =    nrElements    +    1; number    =    IO.read_int (); } }  static private void computeTheAverage () { int sum    =    0; for (int    x    =    0;    x    <    nrElements;    x + +) { sum    =    sum    +    a [x]; } average    =    (double) sum    /    (double) nrElements; }  static private void displayTheNumbersAboveAverage () { for (int    x    =    0;    x    <    nrElements;    x    =    x    +    1) { if (a [x]    >    average) { IO.println (a [x]); } }